CBSE[OUTSIDE DELHI]_X_Mathematics_2019_Set_II

The given quadratic equation is:

           4x² –12x – k = 0

         Comparing with ax² + bx + c = 0, we get

          a = 4, b = – 12 and c = – k

         Since, roots are not real. So, D < 0,
    i.e.,              b² – 4ac < 0

                (– 12)² – 4×4×– k < 0

                            144 + 16k < 0

                                       144 < –16k

                                        – 9 > k

         Therefore, k is a real number smaller than – 9.

Since, 2² × 5³ × 3² × 17 = (2×5)×(2×5)×2×3²×17

                                             = 10 × 10 × 2 × 9 × 17
As there are two 10’s. So, number of zeroes in the end of number obtained by given product is two.