Science 2005 CBSE [ All India ] Set III

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  • Q1

    Write the chemical equation to represent the reaction taking place when copper oxide is heated in a stream of hydrogen.

    Marks:1
    Answer:

    CuO + H2  Cu + H2O

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  • Q2

    Name two metals both of which are very ductile as well as very malleable.

    Marks:1
    Answer:

    Silver and Gold.

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  • Q3

    A wire of resistance 10 ohm is bent in the form of a closed circle. What is the effective resistance between the two points at the ends of any diameter of the circle?

    Marks:1
    Answer:

    Effective resistance (R) between the two points at the end of the diameter of the circle is a combination of two 5 ohm resistances.                             
    1/R = 1/5 +1/5
    1/R = 2/5
    R = 2.5 ohm

     

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  • Q4

    What is the function of genes in an organism?

    Marks:1
    Answer:

    Genes are the segments of DNA which control the traits and characteristics of an individual.

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  • Q5

    Why is it necessary to conserve our environment?

    Marks:1
    Answer:

    We are the part of our environment and fulfill our needs through the environment. Any kind of harm will finally affect us hence we need to conserve our environment.

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  • Q6

    What is observed when a mixture of hydrogen and chlorine is exposed to sunlight? What is the product formed?

    Marks:1
    Answer:

    Hydrogen reacts with chlorine in the presenec of sunlight to form hydrogen chloride.

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  • Q7

    A wire of resistance 20 ohm is bent in the form of a closed circle. What is the effective resistance between the two points at the ends of any diameter of the circle?

    Marks:1
    Answer:

    Effective resistance (R) between the two points at the end diameter of the circle is a combination of two 10 ohm resistances.
    1/R = 1/10 +1/10
     1/R = 2/10                               
    R = 5 ohm

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  • Q8

    What is a genetically modified organism (GMO)?

    Marks:1
    Answer:

    Out of syllabus.

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  • Q9

    Light enters from air into a glass plate which has a refractive index of 1.50. Calculate the speed of light in glass. The speed of light in air is 3.0 x 108 ms-1.

    Marks:2
    Answer:

    Speed of light in air = 3.0 x 108 ms-1
    Let, speed of light in glass = v
    Refractive index of glass (n) = 1.50
    n = speed of light in air/speed of light in glass
     1.50 = (3.0 x 108) / v
     Or,v = (3.0 x 108) / 1.50
     Or,v = 2.0 x 108 ms-1

     

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  • Q10

    What happens when crystals of washing soda are left open in dry air? What is this change named as? Name two industries based on use of washing soda.

    Marks:2
    Answer:

    When crystals of washing soda are left open in air, the crystals lose 9 of their water molecules.
    Second part of the question is out of syllabus.
    Two industries based on washing soda are glass and soap industries.

     

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