CBSE[Delhi]_XII_Mathematics_2016_Set(02)
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Q1Marks:1View Answer
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Q5Marks:1View Answer
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Q6Marks:1View Answer
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Q7
Show that the equation of normal at any point t on the curve x= 3 cos t – cos3t and y = 3 sin t – sin3 t is 4(y cos3t – x sin3 t) = 3 sin 4t.
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Q8Marks:4View Answer
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Q9Marks:4View Answer
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Q10Marks:4View Answer
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